What is the integral from 0 to 6 of 3x^2 ?

The integral from 0 to 6 of 3x^2 is 216

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 6 of 3x^2

\int_{0}^{6} 3 x^{2} d x

216

Solution steps

\int_{0}^{6} 3 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{6} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{6}

= 3 [\frac{x ^{3}}{3}]_{0}^{6}

Compute the boundaries:

72

= 3 \cdot 72

Simplify

= 216

\int_{1}^{2} cos (nπ x) d x

\int_{x}^{1} 1 + t^{2} d t

\int_{0}^{4} π (x^{2})^{2} d x

\int_{3}^{6} (9 - 2 x) d x

\int_{0}^{π} \frac{1}{2} (4 sin (x))^{2} d x

What is the integral from 0 to 6 of 3x^2 ?
The integral from 0 to 6 of 3x^2 is 216