What is the integral from 1 to 4 of-6/(x^2) ?

The integral from 1 to 4 of-6/(x^2) is -9/2

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integral from 1 to 4 of-6/(x^2)

\int_{1}^{4} - \frac{6}{x ^{2}} d x

- \frac{9}{2}

Decimal

- 4.5

Solution steps

\int_{1}^{4} - \frac{6}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 6 \cdot \int_{1}^{4} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{4}

= - 6 [- \frac{1}{x}]_{1}^{4}

Compute the boundaries:

\frac{3}{4}

= - 6 \cdot \frac{3}{4}

Simplify

= - \frac{9}{2}

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What is the integral from 1 to 4 of-6/(x^2) ?
The integral from 1 to 4 of-6/(x^2) is -9/2