What is the integral from 5 to 8 of 1/(x-4) ?

The integral from 5 to 8 of 1/(x-4) is 2ln(2)

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integral from 5 to 8 of 1/(x-4)

\int_{5}^{8} \frac{1}{x - 4} d x

2 ln (2)

Decimal

1.38629 \dots

Solution steps

\int_{5}^{8} \frac{1}{x - 4} d x

Apply u-substitution

: \int_{1}^{4} \frac{1}{u} d u

= \int_{1}^{4} \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= [ln ∣ u ∣]_{1}^{4}

Compute the boundaries:

2 ln (2)

= 2 ln (2)

\int_{- 2}^{2} r 25 - r^{2} d r

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\int_{0}^{2} (2 x - 9) (8 x^{2} + 4) d x

\int_{x^{2}}^{x} (1 + 2 y) d y

What is the integral from 5 to 8 of 1/(x-4) ?
The integral from 5 to 8 of 1/(x-4) is 2ln(2)