What is the integral from 0 to 2pi of 9 ?

The integral from 0 to 2pi of 9 is 18pi

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integral from 0 to 2pi of 9

\int_{0}^{2 π} 9 d θ

18 π

Decimal

56.54866 \dots

Solution steps

\int_{0}^{2 π} 9 d θ

Integral of a constant:

\int a d x = a x

= [9 θ]_{0}^{2 π}

Compute the boundaries:

18 π

= 18 π

\int_{0}^{1} (1 - x^{2})^{\frac{- 1}{2}} d x

\int_{0}^{1} 6 x 4 x^{2} + 1 d x

\int_{0}^{2} 4 x - x^{2} - x^{2} d x

\int_{0}^{10} e^{- 2 x} d x

\int_{1}^{3} x^{3} + 2 x^{2} - 5 x + 2 d x

What is the integral from 0 to 2pi of 9 ?
The integral from 0 to 2pi of 9 is 18pi