What is the integral from 0 to pi/2 of 3cos(t) ?

The integral from 0 to pi/2 of 3cos(t) is 3

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integral from 0 to pi/2 of 3cos(t)

\int_{0}^{\frac{π}{2}} 3 cos (t) d t

3

Solution steps

\int_{0}^{\frac{π}{2}} 3 cos (t) d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{\frac{π}{2}} cos (t) d t

Use the common integral:

\int cos (t) d t = sin (t)

= 3 [sin (t)]_{0}^{\frac{π}{2}}

Compute the boundaries:

1

= 3 \cdot 1

Simplify

= 3

\int_{0}^{\frac{1}{2}} 4 x e^{2 x} d x

\int_{0}^{\frac{π}{2}} 9 sin^{3} (θ) d θ

\int_{- 2}^{x} (8 t^{2} - 7 t) d t

\int_{0}^{\infty} e^{- 3} d x

\int_{- 1}^{3} x (x^{2} - 3) d x

What is the integral from 0 to pi/2 of 3cos(t) ?
The integral from 0 to pi/2 of 3cos(t) is 3