What is the integral from-pi to pi of tcos(nt) ?

The integral from-pi to pi of tcos(nt) is 0

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integral from-pi to pi of tcos(nt)

\int_{- π}^{π} t cos (n t) d t

0

Solution steps

\int_{- π}^{π} t cos (n t) d t

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

t cos (n t) :

Odd

= 0

\int_{0}^{1} y (- 1 + y + e - e^{y}) d y

\int_{4}^{6} t^{2} - 2 t - 8 d t

\int_{0}^{x^{2}} sin (2 t) d t

\int_{0}^{1} ln (x^{2} + 5) d x

\int_{- 8}^{4} (- 2 x + 8) d x

What is the integral from-pi to pi of tcos(nt) ?
The integral from-pi to pi of tcos(nt) is 0