en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of y+1/2

Solution

\int_{0}^{1} y + \frac{1}{2} d y

Solution

1

Solution steps

\int_{0}^{1} y + \frac{1}{2} d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} y d y + \int_{0}^{1} \frac{1}{2} d y

\int_{0}^{1} y d y = \frac{1}{2}

\int_{0}^{1} \frac{1}{2} d y = \frac{1}{2}

= \frac{1}{2} + \frac{1}{2}

Simplify

\frac{1}{2} + \frac{1}{2} : 1

= 1

Graph

Popular Examples

integral from 0 to 2 of x/(x^2+2)

\int_{0}^{2} \frac{x}{x ^{2} + 2} d x

integral from-9 to 9 of e

\int_{- 9}^{9} e d x

integral from 0 to 3 of (2x)/((x^2+4)^2)

\int_{0}^{3} \frac{2 x}{( x ^{2} + 4 ) ^{2}} d x

integral from 0 to t of y(u)sin(t-u)

\int_{0}^{t} y (u) sin (t - u) d u

integral from x to sqrt(x of)(sin(y))/y

\int_{x}^{x} \frac{sin ( y )}{y} d y

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of y+1/2 ?
The integral from 0 to 1 of y+1/2 is 1