What is the integral from 0 to 40 of sin(sqrt(x)) ?

The integral from 0 to 40 of sin(sqrt(x)) is 2(sin(2sqrt(10))-2sqrt(10)cos(2sqrt(10)))

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integral from 0 to 40 of sin(sqrt(x))

\int_{0}^{40} sin (x) d x

2 (sin (210) - 210 cos (210))

Decimal

- 12.55557 \dots

Solution steps

\int_{0}^{40} sin (x) d x

Apply u-substitution

: \int_{0}^{210} sin (u) \cdot 2 u d u

= \int_{0}^{210} sin (u) \cdot 2 u d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{210} sin (u) u d u

Apply Integration By Parts

: [- u cos (u) - \int - cos (u) d u]_{0}^{210}

= 2 [- u cos (u) - \int - cos (u) d u]_{0}^{210}

\int - cos (u) d u = - sin (u)

= 2 [- u cos (u) - (- sin (u))]_{0}^{210}

Simplify

= 2 [- u cos (u) + sin (u)]_{0}^{210}

Compute the boundaries:

sin (210) - 210 cos (210)

= 2 (sin (210) - 210 cos (210))

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What is the integral from 0 to 40 of sin(sqrt(x)) ?
The integral from 0 to 40 of sin(sqrt(x)) is 2(sin(2sqrt(10))-2sqrt(10)cos(2sqrt(10)))