What is the integral from-pi/2 to pi/2 of ucos(u) ?

The integral from-pi/2 to pi/2 of ucos(u) is 0

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integral from-pi/2 to pi/2 of ucos(u)

\int_{- \frac{π}{2}}^{\frac{π}{2}} u cos (u) d u

0

Solution steps

\int_{- \frac{π}{2}}^{\frac{π}{2}} u cos (u) d u

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

u cos (u) :

Odd

= 0

\int_{- 2}^{1} (2 x + 2) d x

\int_{0}^{π} (9 e^{x} + 6 sin (x)) d x

\int_{1}^{x} 2 (1 - \frac{1}{x ^{2}}) d x

\int_{5}^{10} \frac{ln ( x )}{x} d x

\int_{2}^{b} 2 x d x

What is the integral from-pi/2 to pi/2 of ucos(u) ?
The integral from-pi/2 to pi/2 of ucos(u) is 0