What is the integral from 1 to 4 of (3/(x^2)) ?

The integral from 1 to 4 of (3/(x^2)) is 9/4

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integral from 1 to 4 of (3/(x^2))

\int_{1}^{4} (\frac{3}{x ^{2}}) d x

\frac{9}{4}

Decimal

2.25

Solution steps

\int_{1}^{4} \frac{3}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{1}^{4} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{4}

= 3 [- \frac{1}{x}]_{1}^{4}

Compute the boundaries:

\frac{3}{4}

= 3 \cdot \frac{3}{4}

Simplify

= \frac{9}{4}

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What is the integral from 1 to 4 of (3/(x^2)) ?
The integral from 1 to 4 of (3/(x^2)) is 9/4