What is the integral from 0 to 0.2 of x ?

The integral from 0 to 0.2 of x is 0.02

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integral from 0 to 0.2 of x

\int_{0}^{0.2} x d x

0.02

Solution steps

\int_{0}^{0.2} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{0.2}

= [\frac{x ^{2}}{2}]_{0}^{0.2}

Simplify

= [0.5 x^{2}]_{0}^{0.2}

Compute the boundaries:

0.02

= 0.02

\int_{0}^{π} t cos (t) sin (t) d t

\int_{- π}^{π} (sin (2 x))^{2} d x

\int_{- 1}^{2} (x^{2} - 3) d x

\int_{- 1}^{1} x + y + z d x

\int_{0}^{r} 0.5 e^{- 0.5 x} d x

What is the integral from 0 to 0.2 of x ?
The integral from 0 to 0.2 of x is 0.02