What is the integral from 0 to t of t^{5/2} ?

The integral from 0 to t of t^{5/2} is (2t^{7/2})/7

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integral from 0 to t of t^{5/2}

\int_{0}^{t} t^{\frac{5}{2}} d t

\frac{2 t ^{\frac{7}{2}}}{7}

Solution steps

\int_{0}^{t} t^{\frac{5}{2}} d t

Apply the Power Rule

: [\frac{2}{7} t^{\frac{7}{2}}]_{0}^{t}

= [\frac{2}{7} t^{\frac{7}{2}}]_{0}^{t}

Compute the boundaries:

\frac{2}{7} t^{\frac{7}{2}}

= \frac{2}{7} t^{\frac{7}{2}}

Simplify

= \frac{2 t ^{\frac{7}{2}}}{7}

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What is the integral from 0 to t of t^{5/2} ?
The integral from 0 to t of t^{5/2} is (2t^{7/2})/7