What is the integral from 1 to 4 of 3sqrt(t) ?

The integral from 1 to 4 of 3sqrt(t) is 14

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 4 of 3sqrt(t)

\int_{1}^{4} 3 t d t

14

Solution steps

\int_{1}^{4} 3 t d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{1}^{4} t d t

Apply the Power Rule

: [\frac{2}{3} t^{\frac{3}{2}}]_{1}^{4}

= 3 [\frac{2}{3} t^{\frac{3}{2}}]_{1}^{4}

Compute the boundaries:

\frac{14}{3}

= 3 \cdot \frac{14}{3}

Simplify

= 14

\int_{0}^{\frac{1}{2}} e^{x - 1} d x

\int_{- 1}^{3} (x^{2} - 1) d x

\int_{- 6}^{4} x - 1 d x

\int_{- 4}^{5} ∣ 2 x ∣ d x

\int_{0}^{5} x - 5 d x

What is the integral from 1 to 4 of 3sqrt(t) ?
The integral from 1 to 4 of 3sqrt(t) is 14