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Popular >

integral from 0 to 5 of (9-3t)

Solution

\int_{0}^{5} (9 - 3 t) d t

Solution

\frac{15}{2}

+1

Decimal

7.5

Solution steps

\int_{0}^{5} 9 - 3 t d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{5} 9 d t - \int_{0}^{5} 3 t d t

\int_{0}^{5} 9 d t = 45

\int_{0}^{5} 3 t d t = \frac{75}{2}

= 45 - \frac{75}{2}

Simplify

45 - \frac{75}{2} : \frac{15}{2}

= \frac{15}{2}

Graph

Popular Examples

integral from-2 to 4 of 1/((x-2)^{2/3)}

\int_{- 2}^{4} \frac{1}{( x - 2 ) ^{\frac{2}{3}}} d x

integral from-1 to 0 of 3x^3

\int_{- 1}^{0} 3 x^{3} d x

integral from 1 to 4 of 2x+1/x

\int_{1}^{4} 2 x + \frac{1}{x} d x

integral from-1 to 1 of 3x^2+5

\int_{- 1}^{1} 3 x^{2} + 5 d x

integral from 0 to 1 of (1-t)^2

\int_{0}^{1} (1 - t)^{2} d t

Frequently Asked Questions (FAQ)

What is the integral from 0 to 5 of (9-3t) ?
The integral from 0 to 5 of (9-3t) is 15/2