What is taylor arctan(x),1 ?

The answer to taylor arctan(x),1 is pi/4+1/2 (x-1)-1/4 (x-1)^2+1/12 (x-1)^3-1/40 (x-1)^5+\ldots

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taylor arctan(x),1

taylor

arctan (x), 1

\frac{π}{4} + \frac{1}{2} (x - 1) - \frac{1}{4} (x - 1)^{2} + \frac{1}{12} (x - 1)^{3} - \frac{1}{40} (x - 1)^{5} + \dots

Solution steps

Apply the Taylor Formula

= \frac{π}{4} + \frac{\frac{d}{d x} ( arctan ( x ) ) ( 1 )}{1 !} (x - 1) + \frac{\frac{d ^{2}}{d x ^{2}} ( arctan ( x ) ) ( 1 )}{2 !} (x - 1)^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( arctan ( x ) ) ( 1 )}{3 !} (x - 1)^{3} + \dots

Evaluate Derivatives

= \frac{π}{4} + \frac{\frac{1}{2}}{1 !} (x - 1) + \frac{- \frac{1}{2}}{2 !} (x - 1)^{2} + \frac{\frac{1}{2}}{3 !} (x - 1)^{3} + \frac{0}{4 !} (x - 1)^{4} + \frac{- 3}{5 !} (x - 1)^{5} + \dots

Refine

= \frac{π}{4} + \frac{1}{2} (x - 1) - \frac{1}{4} (x - 1)^{2} + \frac{1}{12} (x - 1)^{3} - \frac{1}{40} (x - 1)^{5} + \dots

\frac{\partial}{\partial z} (- 5 e^{3 x + 4 y} sin (5 z))

\int (e^{x} - x^{e}) d x

4 t e^{- 3 t}

x \to - \infty lim (\frac{6 x ^{2} + 5 x ^{\frac{1}{3}}}{9 x ^{4} + 7})

n = 1 \sum \infty n^{n} x^{n}

What is taylor arctan(x),1 ?
The answer to taylor arctan(x),1 is pi/4+1/2 (x-1)-1/4 (x-1)^2+1/12 (x-1)^3-1/40 (x-1)^5+\ldots