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Popular >

integral from 0 to 1 of 2-x^2-x

Solution

\int_{0}^{1} 2 - x^{2} - x d x

Solution

\frac{7}{6}

+1

Decimal

1.16666 \dots

Solution steps

\int_{0}^{1} 2 - x^{2} - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 2 d x - \int_{0}^{1} x^{2} d x - \int_{0}^{1} x d x

\int_{0}^{1} 2 d x = 2

\int_{0}^{1} x^{2} d x = \frac{1}{3}

\int_{0}^{1} x d x = \frac{1}{2}

= 2 - \frac{1}{3} - \frac{1}{2}

Simplify

2 - \frac{1}{3} - \frac{1}{2} : \frac{7}{6}

= \frac{7}{6}

Graph

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\int_{1}^{7} \frac{6}{1 - 3 x} d x

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\int_{0}^{1} sin^{3} (x) d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of 2-x^2-x ?
The integral from 0 to 1 of 2-x^2-x is 7/6