What is the integral from 1 to infinity of e^{x^2} ?

The integral from 1 to infinity of e^{x^2} is diverges

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integral from 1 to infinity of e^{x^2}

\int_{1}^{\infty} e^{x^{2}} d x

diverges

Solution steps

\int_{1}^{\infty} e^{x^{2}} d x

Compute the indefinite integral:

\int e^{x^{2}} d x = \frac{π}{2} erfi (x) + C

Compute the boundaries:

\int_{1}^{\infty} e^{x^{2}} d x =

diverges

= diverges

\int_{0}^{3} (3 x^{2} - x^{3}) d x

\int_{0}^{4} 8 x + x d x

\int_{- 1}^{1} - 6 x^{3} - 16 x^{2} + 6 x + 16 d x

\int_{0}^{2} \frac{x ^{2}}{x ^{3} + 2} d x

\int_{1}^{\infty} \frac{2}{3 x + 1} d x

What is the integral from 1 to infinity of e^{x^2} ?
The integral from 1 to infinity of e^{x^2} is diverges