What is the integral from 1 to 2 of kx ?

The integral from 1 to 2 of kx is (3k)/2

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integral from 1 to 2 of kx

\int_{1}^{2} k x d x

\frac{3 k}{2}

Solution steps

\int_{1}^{2} k x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= k \cdot \int_{1}^{2} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{1}^{2}

= k [\frac{x ^{2}}{2}]_{1}^{2}

Compute the boundaries:

\frac{3}{2}

= k \frac{3}{2}

Simplify

= \frac{3 k}{2}

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What is the integral from 1 to 2 of kx ?
The integral from 1 to 2 of kx is (3k)/2