What is the integral from 1 to 7 of (1/(x^2)) ?

The integral from 1 to 7 of (1/(x^2)) is 6/7

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integral from 1 to 7 of (1/(x^2))

\int_{1}^{7} (\frac{1}{x ^{2}}) d x

\frac{6}{7}

Decimal

0.85714 \dots

Solution steps

\int_{1}^{7} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{7}

= [- \frac{1}{x}]_{1}^{7}

Compute the boundaries:

\frac{6}{7}

= \frac{6}{7}

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What is the integral from 1 to 7 of (1/(x^2)) ?
The integral from 1 to 7 of (1/(x^2)) is 6/7