What is the integral from 0 to 7 of g(x) ?

The integral from 0 to 7 of g(x) is (49g)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 7 of g(x)

\int_{0}^{7} g (x) d x

\frac{49 g}{2}

Solution steps

\int_{0}^{7} gx d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= g \cdot \int_{0}^{7} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{7}

= g [\frac{x ^{2}}{2}]_{0}^{7}

Compute the boundaries:

\frac{49}{2}

= g \frac{49}{2}

Simplify

= \frac{49 g}{2}

\int_{1}^{\infty} \frac{2}{3 x + 3} d x

\int_{1}^{2} \frac{v ^{4} + 3 v ^{5}}{v ^{3}} d v

\int_{0}^{π} \frac{1}{2} sin^{2} (x) d x

\int_{- 1}^{3} 4^{x} d x

\int_{1}^{2} x^{4} - x d x

What is the integral from 0 to 7 of g(x) ?
The integral from 0 to 7 of g(x) is (49g)/2