What is the integral from-1 to 1 of 3x^5-3x^2-3x+3 ?

The integral from-1 to 1 of 3x^5-3x^2-3x+3 is 4

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integral from-1 to 1 of 3x^5-3x^2-3x+3

\int_{- 1}^{1} 3 x^{5} - 3 x^{2} - 3 x + 3 d x

4

Solution steps

\int_{- 1}^{1} 3 x^{5} - 3 x^{2} - 3 x + 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 3 x^{5} d x - \int_{- 1}^{1} 3 x^{2} d x - \int_{- 1}^{1} 3 x d x + \int_{- 1}^{1} 3 d x

\int_{- 1}^{1} 3 x^{5} d x = 0

\int_{- 1}^{1} 3 x^{2} d x = 2

\int_{- 1}^{1} 3 x d x = 0

\int_{- 1}^{1} 3 d x = 6

= 0 - 2 - 0 + 6

Simplify

= 4

\int_{0}^{2} (3 x^{2} e^{2 x^{3}}) d x

\int_{0}^{\frac{π}{8}} sin (4 x) d x

\int_{0}^{8} - t^{2} + 3 t + 32 d t

\int_{- 2}^{9} - x \cdot cos (x) d x

\int_{0}^{1} 1 x^{2} d x

What is the integral from-1 to 1 of 3x^5-3x^2-3x+3 ?
The integral from-1 to 1 of 3x^5-3x^2-3x+3 is 4