What is the integral from e^5 to e^9 of (ln(x))/x ?

The integral from e^5 to e^9 of (ln(x))/x is 28

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integral from e^5 to e^9 of (ln(x))/x

\int_{e^{5}}^{e^{9}} \frac{ln ( x )}{x} d x

28

Solution steps

\int_{e^{5}}^{e^{9}} \frac{ln ( x )}{x} d x

Apply u-substitution

: \int_{5}^{9} u d u

= \int_{5}^{9} u d u

Apply the Power Rule

: [\frac{u ^{2}}{2}]_{5}^{9}

= [\frac{u ^{2}}{2}]_{5}^{9}

Compute the boundaries:

28

= 28

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\int_{1}^{4} (8 x^{2} - 6 x + 4) d x

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\int_{2}^{4} \frac{1}{x - 2} d x

What is the integral from e^5 to e^9 of (ln(x))/x ?
The integral from e^5 to e^9 of (ln(x))/x is 28