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Popular >

integral from 1 to 3 of (x^2+4)

Solution

\int_{1}^{3} (x^{2} + 4) d x

Solution

\frac{50}{3}

+1

Decimal

16.66666 \dots

Solution steps

\int_{1}^{3} x^{2} + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} x^{2} d x + \int_{1}^{3} 4 d x

\int_{1}^{3} x^{2} d x = \frac{26}{3}

\int_{1}^{3} 4 d x = 8

= \frac{26}{3} + 8

Simplify

\frac{26}{3} + 8 : \frac{50}{3}

= \frac{50}{3}

Graph

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\int_{1}^{2} 2 t \cdot e^{t^{2}} d t

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\int_{0}^{1} x^{6} (2 + 2 x^{7})^{4} d x

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\int_{- 2}^{2} (3 x^{4} - 2 x + 1) d x

integral from-1 to 1 of 1/v

\int_{- 1}^{1} \frac{1}{v} d v

integral from 1 to 3 of 3x^2ln(2x^3)

\int_{1}^{3} 3 x^{2} ln (2 x^{3}) d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 3 of (x^2+4) ?
The integral from 1 to 3 of (x^2+4) is 50/3