What is the integral from 0 to 2pi of 1250 ?

The integral from 0 to 2pi of 1250 is 2500pi

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integral from 0 to 2pi of 1250

\int_{0}^{2 π} 1250 d θ

2500 π

Decimal

7853.98163 \dots

Solution steps

\int_{0}^{2 π} 1250 d θ

Integral of a constant:

\int a d x = a x

= [1250 θ]_{0}^{2 π}

Compute the boundaries:

2500 π

= 2500 π

\int_{\frac{1}{2}}^{3} 2 - \frac{1}{x} d x

\int_{- 1}^{1} (1 + x^{2}) d x

\int_{0}^{1} (- 3 x^{2} + 4 x + 3) d x

\int_{0}^{1} \frac{1}{1 + 2 x - 1} d x

\int_{1}^{2} \frac{x ^{3} - 2 x - 2}{x} d x

What is the integral from 0 to 2pi of 1250 ?
The integral from 0 to 2pi of 1250 is 2500pi