What is the limit as x approaches 2 of \sqrt[3]{(x^3-8)/(x-2)} ?

The limit as x approaches 2 of \sqrt[3]{(x^3-8)/(x-2)} is cube root of 12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 2 of \sqrt[3]{(x^3-8)/(x-2)}

Decimal Notation

2.28942 \dots

Solution steps

x \to a lim [f (x)]^{b} = [x \to a lim f (x)]^{b}

With the exception of indeterminate form

Simplify

\frac{x ^{3} - 8}{x - 2} : x^{2} + 2 x + 4

Plug in the value

x = 2

Simplify

\frac{d}{d x} (\frac{3}{5} x^{\frac{5}{3}})

1 + x

\frac{d}{d x} (\frac{e ^{x} + 1}{e ^{x} + 2})

x \to 2 lim (\frac{x ^{3} - 8}{x - 2})

\frac{d}{d t} (e^{2 t} cos (t))

What is the limit as x approaches 2 of \sqrt[3]{(x^3-8)/(x-2)} ?
The limit as x approaches 2 of \sqrt[3]{(x^3-8)/(x-2)} is cube root of 12