What is the integral from-2 to 1 of 2x^2 ?

The integral from-2 to 1 of 2x^2 is 6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-2 to 1 of 2x^2

\int_{- 2}^{1} 2 x^{2} d x

6

Solution steps

\int_{- 2}^{1} 2 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{- 2}^{1} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{- 2}^{1}

= 2 [\frac{x ^{3}}{3}]_{- 2}^{1}

Compute the boundaries:

3

= 2 \cdot 3

Simplify

= 6

\int_{- 1}^{1} (x^{2} - x) (x + 1) d x

\int_{3}^{5} 80 - \frac{240}{x + 4} d x

\int_{0}^{3} - 10 x d x

\int_{0}^{5} t e^{- s t} d t

\int_{1}^{9} 8 u d u

What is the integral from-2 to 1 of 2x^2 ?
The integral from-2 to 1 of 2x^2 is 6