What is the integral from 4 to 3 of (sin(x)) ?

The integral from 4 to 3 of (sin(x)) is cos(4)-cos(3)

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integral from 4 to 3 of (sin(x))

\int_{4}^{3} (sin (x)) d x

cos (4) - cos (3)

Decimal Notation

0.33634 \dots

Solution steps

\int_{4}^{3} sin (x) d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{3}^{4} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= - [- cos (x)]_{3}^{4}

Compute the boundaries:

- cos (4) + cos (3)

= - (- cos (4) + cos (3))

Simplify

= cos (4) - cos (3)

\int_{0}^{1} 2^{x} \cdot 3^{x} d x

\int_{0}^{1} x 33 x^{2} + 16 d x

\int_{0}^{5} 16 - y^{2} d y

\int_{1}^{4} 2 x - 4 d x

\int_{- 1}^{0} \frac{1}{( x + 1 ) ^{\frac{1}{3}}} d x

What is the integral from 4 to 3 of (sin(x)) ?
The integral from 4 to 3 of (sin(x)) is cos(4)-cos(3)