What is the integral from 1 to sqrt(x of)sin(t) ?

The integral from 1 to sqrt(x of)sin(t) is -cos(sqrt(x))+cos(1)

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integral from 1 to sqrt(x of)sin(t)

\int_{1}^{x} sin (t) d t

- cos (x) + cos (1)

Solution steps

\int_{1}^{x} sin (t) d t

Use the common integral:

\int sin (t) d t = - cos (t)

= [- cos (t)]_{1}^{x}

Compute the boundaries:

- cos (x) + cos (1)

= - cos (x) + cos (1)

\int_{0}^{1} (3 x)^{2} - (3 x^{2})^{2} d x

\int_{0}^{4} \frac{x}{16 + x ^{2}} d x

\int_{7}^{x} t^{2} + 15 d t

\int_{- 1}^{1} 2 - 2 y^{2} d y

\int_{1}^{2} (1 + cos (x))^{2} d x

What is the integral from 1 to sqrt(x of)sin(t) ?
The integral from 1 to sqrt(x of)sin(t) is -cos(sqrt(x))+cos(1)