What is the integral from 1 to infinity of 1/(x^{0.99)} ?

The integral from 1 to infinity of 1/(x^{0.99)} is diverges

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integral from 1 to infinity of 1/(x^{0.99)}

\int_{1}^{\infty} \frac{1}{x ^{0.99}} d x

diverges

Solution steps

\int_{1}^{\infty} \frac{1}{x ^{0.99}} d x

Compute the indefinite integral:

\int \frac{1}{x ^{0.99}} d x = 100 x^{0.01} + C

Compute the boundaries:

\int_{1}^{\infty} \frac{1}{x ^{0.99}} d x =

diverges

= diverges

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What is the integral from 1 to infinity of 1/(x^{0.99)} ?
The integral from 1 to infinity of 1/(x^{0.99)} is diverges