What is the integral from 1 to 2 of (x^2+2)/(x^2) ?

The integral from 1 to 2 of (x^2+2)/(x^2) is 2

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integral from 1 to 2 of (x^2+2)/(x^2)

\int_{1}^{2} \frac{x ^{2} + 2}{x ^{2}} d x

2

Solution steps

\int_{1}^{2} \frac{x ^{2} + 2}{x ^{2}} d x

Expand

\frac{x ^{2} + 2}{x ^{2}} : 1 + \frac{2}{x ^{2}}

= \int_{1}^{2} 1 + \frac{2}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 1 d x + \int_{1}^{2} \frac{2}{x ^{2}} d x

\int_{1}^{2} 1 d x = 1

\int_{1}^{2} \frac{2}{x ^{2}} d x = 1

= 1 + 1

Simplify

= 2

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What is the integral from 1 to 2 of (x^2+2)/(x^2) ?
The integral from 1 to 2 of (x^2+2)/(x^2) is 2