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Popular >

integral from 0 to 4 of (3t-8)

Solution

\int_{0}^{4} (3 t - 8) d t

Solution

- 8

Solution steps

\int_{0}^{4} 3 t - 8 d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 3 t d t - \int_{0}^{4} 8 d t

\int_{0}^{4} 3 t d t = 24

\int_{0}^{4} 8 d t = 32

= 24 - 32

Simplify

= - 8

Popular Examples

integral from 2 to 6 of x^2-3x

\int_{2}^{6} x^{2} - 3 x d x

integral from-2 to 1 of (3-x^2)-(x+1)

\int_{- 2}^{1} (3 - x^{2}) - (x + 1) d x

integral from 0 to t of xe^{-x^2}

\int_{0}^{t} x e^{- x^{2}} d x

integral from 0 to pi/2 of sec^3(x)

\int_{0}^{\frac{π}{2}} sec^{3} (x) d x

integral from 1 to 2 of x^2+x^{-2}

\int_{1}^{2} x^{2} + x^{- 2} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of (3t-8) ?
The integral from 0 to 4 of (3t-8) is -8