What is the integral from 0 to pi/2 of-6sin(x) ?

The integral from 0 to pi/2 of-6sin(x) is -6

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integral from 0 to pi/2 of-6sin(x)

\int_{0}^{\frac{π}{2}} - 6 sin (x) d x

- 6

Solution steps

\int_{0}^{\frac{π}{2}} - 6 sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 6 \cdot \int_{0}^{\frac{π}{2}} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= - 6 [- cos (x)]_{0}^{\frac{π}{2}}

Compute the boundaries:

1

= - 6 \cdot 1

Simplify

= - 6

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What is the integral from 0 to pi/2 of-6sin(x) ?
The integral from 0 to pi/2 of-6sin(x) is -6