What is the integral from 1 to 3 of 3/(x^4) ?

The integral from 1 to 3 of 3/(x^4) is 26/27

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integral from 1 to 3 of 3/(x^4)

\int_{1}^{3} \frac{3}{x ^{4}} d x

\frac{26}{27}

Decimal Notation

0.96296 \dots

Solution steps

\int_{1}^{3} \frac{3}{x ^{4}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{1}^{3} \frac{1}{x ^{4}} d x

Apply the Power Rule

: [- \frac{1}{3 x ^{3}}]_{1}^{3}

= 3 [- \frac{1}{3 x ^{3}}]_{1}^{3}

Compute the boundaries:

\frac{26}{81}

= 3 \cdot \frac{26}{81}

Simplify

= \frac{26}{27}

\int_{0}^{1} \frac{2 x}{x ^{2} + 4} d x

\int_{- 2}^{3} (x^{2} - 2) d x

\int_{- 1}^{3} (x^{2} + 3)^{3} x d x

\int_{1}^{3} 1 + x d x

\int_{- 2}^{2} 10 x^{9} + 25 x^{17} d x

What is the integral from 1 to 3 of 3/(x^4) ?
The integral from 1 to 3 of 3/(x^4) is 26/27