What is the integral from 0 to 1 of-6s ?

The integral from 0 to 1 of-6s is -3

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integral from 0 to 1 of-6s

\int_{0}^{1} - 6 s d s

- 3

Solution steps

\int_{0}^{1} - 6 s d s

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 6 \cdot \int_{0}^{1} s d s

Apply the Power Rule

: [\frac{s ^{2}}{2}]_{0}^{1}

= - 6 [\frac{s ^{2}}{2}]_{0}^{1}

Compute the boundaries:

\frac{1}{2}

= - 6 \cdot \frac{1}{2}

Simplify

= - 3

\int_{0}^{\frac{π}{2}} csc^{2} (x) d x

\int_{- 4}^{3} - x^{3} + 27 x + 140 - 6 x^{2} d x

\int_{0}^{2} x - x^{2} d x

\int_{0}^{\frac{π}{2}} sin^{5} (θ) d θ

\int_{0}^{2 π} (cos (x))^{6} d x