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Popular >

integral from 0 to 1 of (4x+7)

Solution

\int_{0}^{1} (4 x + 7) d x

Solution

9

Solution steps

\int_{0}^{1} 4 x + 7 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 4 x d x + \int_{0}^{1} 7 d x

\int_{0}^{1} 4 x d x = 2

\int_{0}^{1} 7 d x = 7

= 2 + 7

Simplify

= 9

Graph

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integral from 2 to 5 of (4x+5)

\int_{2}^{5} (4 x + 5) d x

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\int_{1}^{2} 12 x^{3} + \frac{6}{x ^{2}} d x

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\int_{- 1}^{1} (x^{2} - 3 x + 3) d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (4x+7) ?
The integral from 0 to 1 of (4x+7) is 9