What is the integral from 2 to 5 of 1/(3x-7) ?

The integral from 2 to 5 of 1/(3x-7) is diverges

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integral from 2 to 5 of 1/(3x-7)

\int_{2}^{5} \frac{1}{3 x - 7} d x

diverges

Solution steps

\int_{2}^{5} \frac{1}{3 x - 7} d x

Find undefined (singularity) points:

x = \frac{7}{3}

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{2}^{\frac{7}{3}} \frac{1}{3 x - 7} d x + \int_{\frac{7}{3}}^{5} \frac{1}{3 x - 7} d x

\int_{2}^{\frac{7}{3}} \frac{1}{3 x - 7} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

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What is the integral from 2 to 5 of 1/(3x-7) ?
The integral from 2 to 5 of 1/(3x-7) is diverges