What is the integral from x^3 to sqrt(x of)y ?

The integral from x^3 to sqrt(x of)y is (x-x^6)/2

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integral from x^3 to sqrt(x of)y

\int_{x^{3}}^{x} y d y

\frac{x - x ^{6}}{2}

Solution steps

\int_{x^{3}}^{x} y d y

Apply the Power Rule

: [\frac{y ^{2}}{2}]_{x^{3}}^{x}

= [\frac{y ^{2}}{2}]_{x^{3}}^{x}

Compute the boundaries:

\frac{x}{2} - \frac{x ^{6}}{2}

= \frac{x}{2} - \frac{x ^{6}}{2}

Simplify

= \frac{x - x ^{6}}{2}

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What is the integral from x^3 to sqrt(x of)y ?
The integral from x^3 to sqrt(x of)y is (x-x^6)/2