What is (\partial)/(\partial z)(xsin(y-z)) ?

The answer to (\partial)/(\partial z)(xsin(y-z)) is -xcos(y-z)

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(\partial)/(\partial z)(xsin(y-z))

\frac{\partial}{\partial z} (x sin (y - z))

- x cos (y - z)

Solution steps

\frac{\partial}{\partial z} (x sin (y - z))

Treat

x, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{\partial}{\partial z} (sin (y - z))

Apply the chain rule:

cos (y - z) \frac{\partial}{\partial z} (y - z)

= cos (y - z) \frac{\partial}{\partial z} (y - z)

\frac{\partial}{\partial z} (y - z) = - 1

= x cos (y - z) (- 1)

Simplify

= - x cos (y - z)

\int \frac{x ^{3}}{u} d x

x^{3} - 3 x^{2} + 3

\int_{0}^{17} x d x

cos^{2} (21 t)

y = 2 sin (x), 0, at x = 0

What is (\partial)/(\partial z)(xsin(y-z)) ?
The answer to (\partial)/(\partial z)(xsin(y-z)) is -xcos(y-z)