What is the integral from 1 to 4 of (e^x)/x ?

The integral from 1 to 4 of (e^x)/x is \Ei(4)-\Ei(1)

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integral from 1 to 4 of (e^x)/x

\int_{1}^{4} \frac{e ^{x}}{x} d x

Ei (4) - Ei (1)

Solution steps

\int_{1}^{4} \frac{e ^{x}}{x} d x

Use the nonelementary integral:

\int \frac{e ^{x}}{x} d x = Ei (x)

= [Ei (x)]_{1}^{4}

Compute the boundaries:

Ei (4) - Ei (1)

= Ei (4) - Ei (1)

\int_{0}^{\infty} e^{- x} \cdot x d x

\int_{0}^{1} (x^{2} - 1) - (- x + 2) d x

\int_{0}^{3} x^{2} + 2 x + 1 d x

\int_{x}^{1} sin (x^{2}) d x

\int_{0}^{1} 2 z d z

What is the integral from 1 to 4 of (e^x)/x ?
The integral from 1 to 4 of (e^x)/x is \Ei(4)-\Ei(1)