What is the integral from 0 to 1 of x/(x^2) ?

The integral from 0 to 1 of x/(x^2) is diverges

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integral from 0 to 1 of x/(x^2)

\int_{0}^{1} \frac{x}{x ^{2}} d x

diverges

Solution steps

\int_{0}^{1} \frac{x}{x ^{2}} d x

Cancel the common factor:

x

= \int_{0}^{1} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{0}^{1}

Compute the boundaries:

diverges

= diverges

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\int_{0}^{k} x \frac{2 x}{k ^{2}} d x

\int_{0}^{a} r^{2} d r

\int_{1}^{2} x^{2} - 5 x - 3 d x

What is the integral from 0 to 1 of x/(x^2) ?
The integral from 0 to 1 of x/(x^2) is diverges