What is the integral from-1 to 1 of tcos(npit) ?

The integral from-1 to 1 of tcos(npit) is 0

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integral from-1 to 1 of tcos(npit)

\int_{- 1}^{1} t cos (nπ t) d t

0

Solution steps

\int_{- 1}^{1} t cos (nπ t) d t

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

t cos (nπ t) :

Odd

= 0

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What is the integral from-1 to 1 of tcos(npit) ?
The integral from-1 to 1 of tcos(npit) is 0