What is the integral from 1 to 5 of 4x^3 ?

The integral from 1 to 5 of 4x^3 is 624

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integral from 1 to 5 of 4x^3

\int_{1}^{5} 4 x^{3} d x

624

Solution steps

\int_{1}^{5} 4 x^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{1}^{5} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{1}^{5}

= 4 [\frac{x ^{4}}{4}]_{1}^{5}

Compute the boundaries:

156

= 4 \cdot 156

Simplify

= 624

\int_{5}^{10} \frac{1}{25} (10 - x) d x

\int_{0}^{5} (x - 1) d x

\int_{0}^{3} x^{2} + 2 x - 8 d x

\int_{0}^{4} (x + 1) d x

\int_{1}^{3} 0.25 d x

What is the integral from 1 to 5 of 4x^3 ?
The integral from 1 to 5 of 4x^3 is 624