What is the integral from 0 to 1 of cos(t^2) ?

The integral from 0 to 1 of cos(t^2) is sqrt(pi/2)\C(sqrt(2/pi)*1)-sqrt(pi/2)\C(sqrt(2/pi)*0)

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integral from 0 to 1 of cos(t^2)

\int_{0}^{1} cos (t^{2}) d t

\frac{π}{2} C (\frac{2}{π} \cdot 1) - \frac{π}{2} C (\frac{2}{π} \cdot 0)

Solution steps

\int_{0}^{1} cos (t^{2}) d t

Use the nonelementary integral:

\int cos (x^{2}) d x = \frac{π}{2} C (\frac{2}{π} x)

= [\frac{π}{2} C (\frac{2}{π} t)]_{0}^{1}

Compute the boundaries:

\frac{π}{2} C (\frac{2}{π} \cdot 1) - \frac{π}{2} C (\frac{2}{π} \cdot 0)

= \frac{π}{2} C (\frac{2}{π} \cdot 1) - \frac{π}{2} C (\frac{2}{π} \cdot 0)

\int_{- 3}^{5} \frac{5}{x ^{5}} d x

\int_{0}^{1} t \cdot e^{t} d t

\int_{0}^{8} - 6 x^{2} - 18 x + 528 d x

\int_{0}^{2 π} \frac{1}{x} d x

\int_{0}^{\frac{3}{2}} x^{2} d x

What is the integral from 0 to 1 of cos(t^2) ?
The integral from 0 to 1 of cos(t^2) is sqrt(pi/2)\C(sqrt(2/pi)*1)-sqrt(pi/2)\C(sqrt(2/pi)*0)