What is the integral from-2 to 0 of 1/(sqrt(x+2)) ?

The integral from-2 to 0 of 1/(sqrt(x+2)) is 2sqrt(2)

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integral from-2 to 0 of 1/(sqrt(x+2))

\int_{- 2}^{0} \frac{1}{x + 2} d x

22

Decimal

2.82842 \dots

Solution steps

\int_{- 2}^{0} \frac{1}{x + 2} d x

Apply u-substitution

: \int_{0}^{2} 2 d u

= \int_{0}^{2} 2 d u

Integral of a constant:

\int a d x = a x

= [2 u]_{0}^{2}

Compute the boundaries:

22

= 22

\int_{0}^{2 x} e^{t^{2} + 5} d t

\int_{0}^{3} t^{2} + 2 t - 3 d t

\int_{4}^{6} x^{2} + 2 x - 6 d x

\int_{0}^{1} 4 e^{- x} d x

\int_{- 1}^{1} (5 - ∣ x ∣) d x

What is the integral from-2 to 0 of 1/(sqrt(x+2)) ?
The integral from-2 to 0 of 1/(sqrt(x+2)) is 2sqrt(2)