What is the integral from 1 to 70 of (70)/(69x^2) ?

The integral from 1 to 70 of (70)/(69x^2) is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 70 of (70)/(69x^2)

\int_{1}^{70} \frac{70}{69 x ^{2}} d x

1

Solution steps

\int_{1}^{70} \frac{70}{69 x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{70}{69} \cdot \int_{1}^{70} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{70}

= \frac{70}{69} [- \frac{1}{x}]_{1}^{70}

Compute the boundaries:

\frac{69}{70}

= \frac{70}{69} \cdot \frac{69}{70}

Simplify

= 1

\int_{- 1}^{3} x^{4} d x

\int_{3}^{4} 3 d x

\int_{- 1}^{0} \frac{x}{( x - 1 ) ^{2}} d x

\int_{5}^{1} 8 x - 16 d x

\int_{0}^{e} \frac{( x ^{2} - 9 )}{x + 3} d x

What is the integral from 1 to 70 of (70)/(69x^2) ?
The integral from 1 to 70 of (70)/(69x^2) is 1