What is the integral from 0 to sqrt(4-y^2-z^2 of)1 ?

The integral from 0 to sqrt(4-y^2-z^2 of)1 is sqrt(4-z^2-y^2)

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integral from 0 to sqrt(4-y^2-z^2 of)1

\int_{0}^{4 - y^{2} - z^{2}} 1 d x

4 - z^{2} - y^{2}

Solution steps

\int_{0}^{4 - y^{2} - z^{2}} 1 d x

Integral of a constant:

\int a d x = a x

= [1 \cdot x]_{0}^{4 - z^{2} - y^{2}}

Simplify

= [x]_{0}^{4 - z^{2} - y^{2}}

Compute the boundaries:

4 - z^{2} - y^{2}

= 4 - z^{2} - y^{2}

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What is the integral from 0 to sqrt(4-y^2-z^2 of)1 ?
The integral from 0 to sqrt(4-y^2-z^2 of)1 is sqrt(4-z^2-y^2)