What is the integral from 5 to 9 of 80-(240)/(x+1) ?

The integral from 5 to 9 of 80-(240)/(x+1) is 320-240ln(5/3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 5 to 9 of 80-(240)/(x+1)

\int_{5}^{9} 80 - \frac{240}{x + 1} d x

320 - 240 ln (\frac{5}{3})

Decimal

197.40185 \dots

Solution steps

\int_{5}^{9} 80 - \frac{240}{x + 1} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{5}^{9} 80 d x - \int_{5}^{9} \frac{240}{x + 1} d x

\int_{5}^{9} 80 d x = 320

\int_{5}^{9} \frac{240}{x + 1} d x = 240 ln (\frac{5}{3})

= 320 - 240 ln (\frac{5}{3})

\int_{3}^{5} - x^{2} + 8 x - 12 d x

\int_{2}^{8} \frac{e ^{\frac{1}{x}}}{x ^{2}} d x

\int_{1}^{2} (\frac{2}{x} - e^{3 x}) d x

\int_{0}^{2} e^{- 5 x} d x

\int_{1}^{2} 8 \cdot e^{4 x - 3} d x

What is the integral from 5 to 9 of 80-(240)/(x+1) ?
The integral from 5 to 9 of 80-(240)/(x+1) is 320-240ln(5/3)