What is the integral from 0 to x^2 of t ?

The integral from 0 to x^2 of t is (x^4)/2

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integral from 0 to x^2 of t

\int_{0}^{x^{2}} t d t

\frac{x ^{4}}{2}

Solution steps

\int_{0}^{x^{2}} t d t

Apply the Power Rule

: [\frac{t ^{2}}{2}]_{0}^{x^{2}}

= [\frac{t ^{2}}{2}]_{0}^{x^{2}}

Compute the boundaries:

\frac{x ^{4}}{2}

= \frac{x ^{4}}{2}

\int_{- 1}^{2} x^{3} - 2 x^{2} - 5 x + 6 d x

\int_{- 1}^{0} x - 1 d x

\int_{0}^{1} \frac{1}{3 - 2 x ^{2}} d x

\int_{0}^{2} (2 x + x) d x

\int_{0}^{l n (6)} e^{4 x} d x

What is the integral from 0 to x^2 of t ?
The integral from 0 to x^2 of t is (x^4)/2