What is the integral from-4 to 2 of 1/(sqrt(x+4)) ?

The integral from-4 to 2 of 1/(sqrt(x+4)) is 2sqrt(6)

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integral from-4 to 2 of 1/(sqrt(x+4))

\int_{- 4}^{2} \frac{1}{x + 4} d x

26

Decimal

4.89897 \dots

Solution steps

\int_{- 4}^{2} \frac{1}{x + 4} d x

Apply u-substitution

: \int_{0}^{6} 2 d u

= \int_{0}^{6} 2 d u

Integral of a constant:

\int a d x = a x

= [2 u]_{0}^{6}

Compute the boundaries:

26

= 26

\int_{0}^{4} - \frac{x}{2} d x

\int_{- 2}^{- 1} - x - 1 d x

\int_{1}^{2} (y - \frac{1}{y ^{2}}) d y

\int_{1}^{x^{2}} 1 + t d t

\int_{2}^{x^{3}} ln (x) d x

What is the integral from-4 to 2 of 1/(sqrt(x+4)) ?
The integral from-4 to 2 of 1/(sqrt(x+4)) is 2sqrt(6)