Solution
Solution
+1
Solution steps
Take the constant out:
Apply Integration By Parts
Simplify
Compute the boundaries:
Popular Examples
integral from 0 to 1 of sqrt(1+r^2)rintegral from-1 to 4 of (-x^2+6x+8-x^2)integral from 0 to 1 of x^{-3/2}integral from 0 to y of sin(x+y)integral from 3 to 6 of 1/(sqrt(x^2-4))
Frequently Asked Questions (FAQ)
What is the integral from 1 to 4 of pi(2/y)^2 ?
The integral from 1 to 4 of pi(2/y)^2 is pi3